-- SIMPLE OUTER - NO NULLS
drop table x if exists;
drop table y if exists;
create table x(a int, b int);
create table y(a int, b int);
insert into x values(2, 1);
insert into x values(5, 1);
insert into y values(1, 1);
insert into y values(2, 1);
insert into y values(3, 1);
insert into y values(4, 1);

/*r1*/ select count(*) from x inner join y on (x.a = y.a);
/*r2*/ select count(*) from x left outer join y on (x.a = y.a);
/*r1*/ select count(*) from y inner join x on (x.a = y.a);
/*r4*/ select count(*) from y left outer join x on (x.a = y.a);

create index idx1 on y(a);
create index idx2 on x(a);

/*r1*/ select count(*) from x inner join y on (x.a = y.a);
/*r2*/ select count(*) from x left outer join y on (x.a = y.a);
/*r1*/ select count(*) from y inner join x on (x.a = y.a);
/*r4*/ select count(*) from y left outer join x on (x.a = y.a);

--MULTIPLE OUTER -- GROUPED
--OWNERS are possible account owners
--ACCOUNTS are existing accounts, each with an owner id
--CREDITS are account transactions
drop table credits if exists;
drop table accounts if exists;
drop table owners if exists;

create table owners(
 id int not null primary key,
 name varchar(100)
 );
create table accounts(
 id int not null primary key,
 accountname varchar(100),
 accountnr int,
 accounttype int,
 ownerid int,
 constraint fk_accounts foreign key (ownerid) references owners(id)
 );
create table credits(
 id int,
 accountid int,
 amount float,
 constraint fk_credits foreign key (accountid) references accounts(id) on update cascade
 );


insert into owners values(1,'John');
insert into owners values(2,'Mary');
insert into owners values(3,'Jane');

insert into accounts values(1,'Bank',5101,0,1);
insert into accounts values(2,'Cash',5202,0,1);
insert into accounts values(3,'Giro',5303,0,2);
insert into accounts values(4,'Invoice',7505,1,1);

insert into credits values(1,1,1000);
insert into credits values(2,1,2000);
insert into credits values(3,2,100);
insert into credits values(4,2,200);

--outer join
/*c7*/select own.*, ac.*, cred.* from owners own
 left outer join accounts ac on own.id = ac.ownerid
 left outer join credits cred on cred.accountid = ac.id

--ACCOUNTS are outer joined with credits to show account balance
/*c4*/select ac.accountname,ac.accountnr,sum(cred.amount) from accounts ac
 left outer join credits cred on cred.accountid=ac.id
 group by ac.accountnr,ac.accountname

--like above but filtered with only one account type
/*c3*/select ac.accountname,ac.accountnr,sum(cred.amount) from accounts ac
 left outer join credits cred on cred.accountid=ac.id
 where accounttype=0
 group by ac.accountnr,ac.accountname

--join like above but condition changed to return only one not-null item from cred table
/*c4*/select ac.accountname,ac.accountnr, cred.amount from accounts ac
 left outer join credits cred on cred.accountid=ac.id and amount=200

--OWNER and ACCOUNT are inner joined then outer joined with credits to show balance
/*c3*/select own.name, ac.accountname,ac.accountnr,sum(cred.amount) from owners own
 inner join accounts ac on own.id = ac.ownerid
 left outer join credits cred on cred.accountid = ac.id
 where accounttype=0
 group by own.name,ac.accountnr,ac.accountname

--OWNER and ACCOUNT are outer joined then outer joined with credits to show balance
/*c5*/select own.name, ac.accountname,ac.accountnr,sum(cred.amount) from owners own
 left outer join accounts ac on own.id = ac.ownerid
 left outer join credits cred on cred.accountid = ac.id
 group by own.name,ac.accountnr,ac.accountname

--ERROR when a condition column has not been defined in the join so far
/*e*/select own.*, ac.*, cred.* from owners own
 left outer join accounts ac on own.id = ac.ownerid and cred.accountid = 1
 left outer join credits cred on cred.accountid = ac.id

--ERROR - join like above but using a functions
/*e*/select ac.accountname,ac.accountnr, cred.amount from accounts ac
 left outer join credits cred on cred.accountid=ac.id and abs(amount) = 200


--MULTIPLE OUTER
--STUDENTS contains id's for students
--TEACHERS contains id's for teachers
--STUDENT_TEACHER links a teacher to a student
CREATE TABLE STUDENT(STUDENT_ID BIGINT NOT NULL PRIMARY KEY);
CREATE TABLE TEACHER(TEACHER_ID BIGINT NOT NULL PRIMARY KEY);
CREATE TABLE STUDENT_TEACHER(STUDENT_ID BIGINT NOT NULL, TEACHER_ID BIGINT NOT NULL);

INSERT INTO STUDENT VALUES (1);
INSERT INTO STUDENT VALUES (2);
INSERT INTO TEACHER VALUES (100);
INSERT INTO STUDENT_TEACHER VALUES (1, 100);

--show all students with their links to teachers, include students without a teacher
/*c2*/SELECT S.STUDENT_ID, T.TEACHER_ID FROM STUDENT S
  LEFT JOIN STUDENT_TEACHER MAP ON S.STUDENT_ID=MAP.STUDENT_ID
  LEFT JOIN TEACHER T ON MAP.TEACHER_ID=T.TEACHER_ID

--filter the above to show students for teacher_id 100
/*c1*/SELECT S.STUDENT_ID, T.TEACHER_ID FROM STUDENT S
  LEFT JOIN STUDENT_TEACHER MAP ON S.STUDENT_ID=MAP.STUDENT_ID
  LEFT JOIN TEACHER T ON MAP.TEACHER_ID=T.TEACHER_ID
  WHERE T.TEACHER_ID = 100;

--filter the first query to show only students with no teacher
/*c1*/SELECT S.STUDENT_ID, T.TEACHER_ID FROM STUDENT S
  LEFT JOIN STUDENT_TEACHER MAP ON S.STUDENT_ID=MAP.STUDENT_ID
  LEFT JOIN TEACHER T ON MAP.TEACHER_ID=T.TEACHER_ID
  WHERE T.TEACHER_ID IS NULL;

--show the result of nonsensical query
--returns one row per STUDENT_ID with TEACHER_ID set to null in each row
/*c2*/SELECT S.STUDENT_ID, T.TEACHER_ID FROM STUDENT S
  LEFT JOIN STUDENT_TEACHER MAP ON S.STUDENT_ID=MAP.STUDENT_ID
  LEFT JOIN TEACHER T ON MAP.TEACHER_ID=T.TEACHER_ID
  AND T.TEACHER_ID IS NULL;

--ANOTHER OUTER WITH AND
create table BASE (ID integer)
create table CHILD(ID integer, BASE_ID integer)
insert into BASE values (1)
insert into CHILD values (1,1)
/*c1*/select BASE.ID,CHILD.ID from BASE left join CHILD on CHILD.BASE_ID=BASE.ID
/*c1*/select BASE.ID,CHILD.ID from BASE left join CHILD on CHILD.BASE_ID=BASE.ID and CHILD.ID>1
/*rISNULL,1*/select COALESCE(CAST(CHILD.ID AS VARCHAR),'ISNULL'),BASE.ID from BASE left join CHILD on CHILD.BASE_ID=BASE.ID and CHILD.ID>1

--bug #736327
create table emp(company_id varchar(10),id varchar(20),supervisor_id varchar(20), primary key (company_id,id));
insert into emp values ('01','1000',null);
insert into emp values ('01','1001','1000');
/*c2*/select id,supervisor_id from emp e left join emp s on
 e.company_id = s.company_id and e.supervisor_id = s.id;
--
--bug #676083
--
DROP TABLE T_BOSS IF EXISTS;
DROP TABLE T_EMPLOYEE IF EXISTS;
CREATE TABLE T_BOSS (FIRST VARCHAR,LAST VARCHAR);
CREATE TABLE T_EMPLOYEE (FIRST VARCHAR,LAST VARCHAR);
INSERT INTO T_BOSS VALUES ('Ludovic','ANCIAUX');
INSERT INTO T_EMPLOYEE VALUES ('Ludovic','ANCIAUX');
INSERT INTO T_EMPLOYEE VALUES ('Bill','GATES');
/*c1*/SELECT * FROM T_EMPLOYEE LEFT JOIN T_BOSS
 ON T_EMPLOYEE.FIRST = T_BOSS.FIRST WHERE T_BOSS.FIRST IS Null;
--
--bug #674025
--
CREATE TABLE boss (id INTEGER PRIMARY KEY, name VARCHAR, UNIQUE(name));
CREATE TABLE employee (id INTEGER PRIMARY KEY, name VARCHAR, bossid INTEGER,
 FOREIGN KEY(bossid) REFERENCES boss (id), UNIQUE(name));
INSERT INTO boss (id, name) VALUES (1, 'phb');
INSERT INTO employee (id, name, bossid) VALUES (2,'dilbert', 1);
INSERT INTO employee (id, name, bossid) VALUES (3, 'wally', null);
/*c2*/SELECT * FROM employee e LEFT JOIN boss b ON (b.id=e.bossid);
/*c2*/SELECT * FROM employee e LEFT JOIN boss b ON (b.id=e.bossid AND e.name='dilbert');
/*c2*/SELECT * FROM employee e LEFT JOIN boss b ON (b.id=e.bossid AND b.name='dilbert');

--bug #959678

CREATE CACHED TABLE propertyvalue (
 id INT, name CHAR(36), value CHAR(255));
INSERT INTO propertyvalue VALUES (1, 'title', 'Foo');
INSERT INTO propertyvalue VALUES (2, 'title', 'Bar');
/*r
 2,2,Bar
*/ SELECT * FROM
 (SELECT id FROM propertyvalue WHERE name = 'title') AS id
 LEFT JOIN
 (SELECT id, value FROM propertyvalue WHERE name = 'title') AS title
 ON id.id = title.id
 WHERE title.value != 'Foo'

--bug #1018584

drop table a if exists;
drop table b if exists;
create table a (aid int, id int);
create table b (bid int, aid int);
insert into a (aid,id) values (1,1);
insert into a (aid,id) values (2,1);
insert into a (aid,id) values (3,2);
insert into a (aid,id) values (4,2);
insert into b (bid,aid) values (1,1);
insert into b (bid,aid) values (2,1);
/*c0*/select * from b left outer join a on b.aId = a.aId where Id =10;
create index idx_test on a (ID);
/*c0*/select * from b left outer join a on b.aId = a.aId where Id =10;
/*c2*/select * from b left outer join a on b.aId = a.aId and Id =10;

--bug #1027143

drop table testc if exists;
drop table testb if exists;
drop table testa if exists;
create table testa (oid int, name varchar(20));
create table testb (oid int, name varchar(20), a_oid int);

insert into testa (oid, name) values(1, 'first');
insert into testa (oid, name) values(2, 'second');
insert into testa (oid, name) values(3, 'third');
insert into testa (oid, name) values(4, 'fourth');
insert into testb (oid, name, a_oid) values(21,'first', 1);
insert into testb (oid, name, a_oid) values(22,'second', null);
insert into testb (oid, name, a_oid) values(23,'third', 2);
insert into testb (oid, name, a_oid) values(24,'fourth', null);
insert into testb (oid, name, a_oid) values(25,'fifth', 3);
insert into testb (oid, name, a_oid) values(26,'sixth', null);

/*r
 1,first,21,first,1
 2,second,23,third,2
 3,third,25,fifth,3
 4,fourth,NULL,NULL,NULL
*/ select * from testa a LEFT OUTER JOIN testb b ON a.oid = b.a_oid

create index idx3 on testb(a_oid)

/*r
 1,first,21,first,1
 2,second,23,third,2
 3,third,25,fifth,3
 4,fourth,NULL,NULL,NULL
*/ select * from testa a LEFT OUTER JOIN testb b ON a.oid = b.a_oid


